JEE, NEET, Foundation & CBSE (JEE Advanced 2018

A man grows into a giant such that his linear dimensions increase by a factor of 9. Assuming that his density remains same, the stress in the leg will change by a factor of :
  1. 9
  2. 81
  3. 1/9
  4. 1/81
A radioactive nucleus A with a half life T, decays into a nucleus B. At t = 0, there is no nucleus B. At sometime t, the ratio of the number of B to that of A is 0.3. Then, t is given by :
  1. t = T log (1.3)
  2. t = T / (log (1.3))
  3. t = (T / 2) (log2/log (1.3))
  4. t = T (log (1.3)/log2)
A time dependent force F = 6t acts on a particle of mass 1 kg. If the particle starts from rest, the work done by the force during the first 1 sec. will be-
  1. 9 Joule
  2. 18 Joule
  3. 22 Joule
  4. 4.5 Joule
At t = 0 the positions and velocities of the two particle are as shown in the figure. They are kept on a smooth surface and being mutually attracted by gravitational force. Then position of the centre of mass at t = 2 sec -
  1. X = 2m
  2. X = 3m
  3. X = 5m
  4. X = 7m
The following observations were taken for determining surface tension T of water by capillary method : Diameter of capillary, D = 1.25 × 10 ⁻² m rise of water, h = 1.45 × 10 ⁻² m Using g = 9.80 m/s² and the simplified relation T = (rhg /2)
  1. 2.4%
  2. 10%
  3. 0.15%
  4. 1.5%
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