Class XI The length of the second’s pendulum on the surface of earth is 1m. The length of second’s pendulum on the surface of moon, where g is 1/6th the value on earth is 1/ 6m 36m 6m 1/ 36m Period of a periodic motion is the ________ interval of time after which the motion is __________. mean, not repeated largest, repeated average, repeated smallest, repeated A particle executes S.H.M along a straight line with amplitude ‘A’. The potential energy is maximum when the displacement is Zero ±± A/2 ±± A2–√ ±± A The maximum displacement of a particle executing S.H.M is 1 cm and the maximum acceleration is (1.57)2(1.57)2 cm/sec, then the time period is 0.25 sec 4.00 sec 1.57 sec 1.5722 sec A particle is executing S.H.M with an amplitude of 4 cm and time period 12 sec. The time taken by the particle in going from its mean position to a position of displacement equal to 2 cm is T1T1..The time taken from this displaced position of 2 cm to reach the extreme position is T2. Therefore, T1T1/ T2T2 will be 41276.0 1/ 3 1 2 Do you really want to submit this quiz? Cancel Submit Quiz