Class VI

Considering inequalities, nine is
  1. < 11
  2. < 5
  3. < 7
  4. > 14
Numerator of fraction is 3 less than denominator. If 5 is subtracted from both numerator and denominator, fraction becomes 4⁄5. fraction was
  1. 11⁄20
  2. 17⁄20
  3. 9⁄13
  4. 11⁄15
By solving inequality 10a < 50, answer will be
  1. a < 5
  2. a < 8
  3. a < 10
  4. a < 50
If sum of 4 consecutive numbers is 98 then equation derived for this statement can be written as
  1. a + (a + 1) + (a + 2) + (a + 3) = 98
  2. a + 1 + 2 + 3 = 98
  3. a + (a + 1) + (a + 2) + (a + 3) = 98a
  4. (a)(1)(2)(3) = 98
Considering inequality, -5 x 0 is
  1. equal to 0 x 8
  2. equal to 0 x -5
  3. equal to 0 x -8
  4. all of above
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