Class VI Considering inequalities, nine is < 11 < 5 < 7 > 14 Numerator of fraction is 3 less than denominator. If 5 is subtracted from both numerator and denominator, fraction becomes 4⁄5. fraction was 11⁄20 17⁄20 9⁄13 11⁄15 By solving inequality 10a < 50, answer will be a < 5 a < 8 a < 10 a < 50 If sum of 4 consecutive numbers is 98 then equation derived for this statement can be written as a + (a + 1) + (a + 2) + (a + 3) = 98 a + 1 + 2 + 3 = 98 a + (a + 1) + (a + 2) + (a + 3) = 98a (a)(1)(2)(3) = 98 Considering inequality, -5 x 0 is equal to 0 x 8 equal to 0 x -5 equal to 0 x -8 all of above Do you really want to submit this quiz? Cancel Submit Quiz